What is the nuclear binding energy for uranium-238 in joules? Assume the following:. Mass defect = 3.2008 x 10-27 kilograms. Use E = mc2, with c = (3 x 108 m/s)2 Select one of the options below as your answer:A. 0.28807 x 10-12 joules B. 2.8807 x 10-12 joules C. 2.8807 x 10-10 joules D. 2.8807 x 10-8 joules E. 3.2008 x 1027 joules

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superman1987 superman1987 · Answer 1 · 2018-07-18T14:34:23+02:00

The correct answer is (C) 2.8807 x 10^-10

The explanation:

According to this formula:

E = MC^2

when E is the nuclear binding energy

and M is the mass defect = 3.2008 x 10^-27 Kg

and C is the speed of light = 3 x 10^8 m/s^2

so, by substitution:

∴ E = 3.2008 x 10^-27 * (3 x 10^8 )^2

= 2.8807 x 10^-10

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mahima6824soni mahima6824soni · Answer 2 · 2022-06-06T13:03:52+02:00

The nuclear binding energy for uranium-238 in joules is 2.8807 x 10⁻¹².

Nuclear binding is the total separation of the nucleus into protons, and electrons.

By the formula

[tex]E = MC^2[/tex]

where E is the nuclear binding energy

M is the mass defect = [tex]3.2008 \times 10^{-27} Kg[/tex]

C is the speed of light = [tex]3 \times 10^8 m/s^2[/tex]

Putting the values in the equation

[tex]3.2008 \times 10^{-27} \times (3 \times 10^8 )^2 = 2.8807 \times 10^{-12}[/tex]

Thus, the correct option is A. 2.8807 x 10⁻¹².

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