contestada

A 0.54-kg ball is thrown vertically upward with an initial speed of 15.5 m/s. What is the potential energy of the ball when it has travelled one-quarter of the distance to its maximum height

Respuesta :

adedayo9

Answer:

16.2J

Explanation:

At the maximum height v = 0

V ^2= u^2 - 2gh (- because since the ball is going upward)

h = u^2 - v^2 / 2g

15.5^2 /20

h = 12.0125

h = 12m

At one quarter of the distance 1/4 × 12 = 3m

Potential energy = mgh

= 0.54 × 10× 3

= 16.2J

Otras preguntas

Q&A Education