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galasalvatori
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Using the basis of a confidence interval, it is found that a value of z = 1.695 should be used making a 91% confidence interval for p.

  • For a confidence value of [tex]\alpha[/tex], the value of z is the z-score which has a p-value of [tex]\frac{1 + \alpha}{2}[/tex].
  • The p-value is found looking at the standard normal table.

In this problem, 91% confidence level, thus [tex]\alpha = 0.91[/tex], and z with a p-value of 0.955 is used. Looking at the standard normal table, it is found that this is z = 1.695.

A similar problem is given at https://brainly.com/question/16951572

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