Answer:
W= 2.16 x 10^5 K, Vf = 18.97 m/s
Explanation:
Solution is attached.
The amount of work performed on the car is 216 kJ and the speed of car be moving at the end is 18.97 m/s.
Work done is the force applied on a body to move it over a distance. Work done to move an object at a distance can be given as,
[tex]W=Fd[/tex]
Here, (F) is the magnitude of force and (d) is the distance traveled.
The force is the product of mass time acceleration force. Thus, the above equation can be given as,
[tex]W=(ma)d[/tex]
Here, (m) is the mass and the (a) is the acceleration.
The mass of the car is 1200 kg and the acceleration of it is 1.2 meters. As the car travels the distance of 150 meters. Therefore,
[tex]W=(1200\times1.2)\times150\\W=216000\rm J\\W=216 kJ[/tex]
Let suppose the final velocity of the car at the end is [tex]v_f[/tex]. As the initial velocity of the car is 0. Therefore, the final velocity of the car by the third equation of motion can be given as,
[tex]v_f^2-(0)^2=2as\\v_f=\sqrt{2\times1.2\times150}\\v_f=18.97\rm m/s[/tex]
Hence, the amount of work performed on the car is 216 kJ and the speed of car be moving at the end is 18.97 m/s.
Learn more about the work done here;
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