Respuesta :
We can solve for both x and y of System A and B to compare the values of x.
System A. Multiply by 4 the first equation and add both equations,
                     12x + 8y = 12
                  +    -2x - 8y = -1
We will be left with equation,Â
                     10x = 11
The value of x is 11/10
System B. Multiply the first equation by -2 and add the equations,
                   2x + 28y = -2
               +   -2x - 8y = -1
We will be left with 20y = -3. Substitute the value of y to any of the equations. This gives a value of x equal to 11/10.Â
The answer therefore is that both systems will have the same value of x's.
                Â
System A. Multiply by 4 the first equation and add both equations,
                     12x + 8y = 12
                  +    -2x - 8y = -1
We will be left with equation,Â
                     10x = 11
The value of x is 11/10
System B. Multiply the first equation by -2 and add the equations,
                   2x + 28y = -2
               +   -2x - 8y = -1
We will be left with 20y = -3. Substitute the value of y to any of the equations. This gives a value of x equal to 11/10.Â
The answer therefore is that both systems will have the same value of x's.
                Â
To compare the values of x, we need to obtain the values of x for both systems.
For system A. Multiply the first equation by 4 and add the equations,
                     12x + 8y = 12
                  +    -2x - 8y = -1
It will yield,Â
                     10x = 11
Then, the value of x is 11/10.
For system B. Multiply the first equation by -2 and add the equations given,
                   2x + 28y = -2
               +   -2x - 8y = -1
It will yield,
20y = -3
Â
We substitute the value of y to any of the equations in system B. This gives a value of x which is equal to 11/10.Â
Therefore, both systems will have the same value of x.
For system A. Multiply the first equation by 4 and add the equations,
                     12x + 8y = 12
                  +    -2x - 8y = -1
It will yield,Â
                     10x = 11
Then, the value of x is 11/10.
For system B. Multiply the first equation by -2 and add the equations given,
                   2x + 28y = -2
               +   -2x - 8y = -1
It will yield,
20y = -3
Â
We substitute the value of y to any of the equations in system B. This gives a value of x which is equal to 11/10.Â
Therefore, both systems will have the same value of x.