Respuesta :
The Gibb's free energy at a certain temperature is calculated through the equation,
ΔG = - RT(ln K)
where K is constant. Substituting the values from the first set of the given,
1.423x10^2 = -(8.314)(25 + 273) x (ln K)
Solving for the value of K gives us an answer of, K = 0.94418
Use the same equation to get the value of ΔG°1200
ΔG = - (8.314)(1200) x (ln 0.94418)
The value of ΔG°1200 is approximately 573.05 kJ
ΔG = - RT(ln K)
where K is constant. Substituting the values from the first set of the given,
1.423x10^2 = -(8.314)(25 + 273) x (ln K)
Solving for the value of K gives us an answer of, K = 0.94418
Use the same equation to get the value of ΔG°1200
ΔG = - (8.314)(1200) x (ln 0.94418)
The value of ΔG°1200 is approximately 573.05 kJ
The Gibb's free energy at a certain temperature is calculated by using the equation,
ΔG = - RT(ln K)
where K is the constant. We calculate this value by using the first conditions,
1.423x10^2 = -(8.314)(25 + 273) x (ln K)
Solving for K,
K = 0.94418
Use the equation for the second set of conditions,
ΔG = - (8.314)(1200) x (ln 0.94418)
ΔG° at 1200 K is approximately 573.05 kJ
ΔG = - RT(ln K)
where K is the constant. We calculate this value by using the first conditions,
1.423x10^2 = -(8.314)(25 + 273) x (ln K)
Solving for K,
K = 0.94418
Use the equation for the second set of conditions,
ΔG = - (8.314)(1200) x (ln 0.94418)
ΔG° at 1200 K is approximately 573.05 kJ