The temperature at 6:00 a.m. was ‐3.5°C. From 6:00 to 7:00, the temperature increased 2.5°C. From 7:00 to 8:00, it decreased by 0.25°C, and from 8:00 to 11:00, the temperature dropped 3.25°C. Which expression shows the temperature in °C at 11:00 a.m.?

The temperature at 600 am was 35C From 600 to 700 the temperature increased 25C From 700 to 800 it decreased by 025C and from 800 to 1100 the temperature droppe class=

Respuesta :

The expression that shows the temperature in °C is [tex]-3.5+2.5+(-0.25)+(-3.25)[/tex].

Step-by-step explanation:

Step 1:

The initial temperature at 6.00 am was [tex]-3.5[/tex] °C.

Step 2:

From 6.00 to 7.00 am, the temperature increased by another 2.5°C, so the temperature at 7.00 am was [tex](-3.5 + 2.5)[/tex] °C.

Step 3:

From 7.00 to 8.00 a.m, the temperature decreased by another 0.25°C, so the temperature at 8.00 am was [tex](-3.5+2.5+(-0.25))[/tex] °C.

Step 4:

From 8.00 to 11.00 a.m, the temperature dropped by another 3.25 °C, so the temperature at 11.00 am was [tex](-3.5+2.5+(-0.25)+-(3.25))[/tex] °C which is represented by the fourth option.

Answer:

A i did did question on think through math think it is the answer

Step-by-step explanation:

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