Step-by-step explanation:
Given is a 45°-45°-90 ° angled triangle.
By 45°-45°-90 ° angled triangle theorem:
side opposite to 45° angle is [tex] \frac{1}{\sqrt 2} [/tex] times of hypotenuse.
[tex] \therefore \: 7 = \frac{1}{ \sqrt{2} } \times m \\ \\ \huge \red{ \boxed{\therefore \: m \: = 7 \sqrt{2} \: units}} \\ \\ n \: = \frac{1}{ \sqrt{2} } \times m \\ \\ \therefore \:n \: = \frac{1}{ \sqrt{2} } \times 7 \sqrt{2} \\ \huge \purple{ \boxed{\therefore \:n \: = 7 \: units}} \\ [/tex]
