Answer:23 seconds
Explanation:
Acceleration(a)=3.87m/s^2
distance(d)=1020m
Initial velocity(u)=0
d=uxt + (axt^2)/2
1020=0xt + (3.87xt^2)/2
1020=(3.87xt^2)/2
Cross multiply
1020x2=3.87xt^2
2040=3.87xt^2
t^2=2040/3.87
t^2=527.13
t=22.95
Time(t) is approximately 23seconds
