For this case we must factor the following expression:
[tex]100k ^ 3-75k ^ 2 + 120k-90[/tex]
We take common factor 5:
[tex]5 (20k ^ 3-15k ^ 2 + 24k-18) =[/tex]
We have two groups within the parentheses:
Group 1: [tex]20k ^ 3-15k ^ 2[/tex]
Group 2: [tex]24k-18[/tex]
We factor each group:
Group 1: [tex]6 (4k-3)[/tex]
Group 2: [tex]5k ^ 2 (4k-3)[/tex]
Rewriting we have:
[tex]5 (5k ^ 2 (4k-3) +6 (4k-3)) =\\5 ((5k ^ 2 + 6) (4k-3))[/tex]
Answer:
[tex]5 (5k ^ 2 + 6) (4k-3)[/tex]
