Please help me I’m terrible at algebra
Answer:
10[tex]\leq[/tex]D+R
D[tex]\geq[/tex]R/3 (or 3D[tex]\geq[/tex]R)
Step-by-step explanation:
Say that D = Decaf and R = Regular
10[tex]\leq[/tex]D+R
D[tex]\geq[/tex]R/3 (or 3D[tex]\geq[/tex]R)