Four ball are simultaneously launched with the same speed from the same height and h above the ground. At the same instant, ball 5 is released from the rest at the same height. Rank in order, from shortest to longest, the amount of time it takes each of these balls to hit the ground ( some maybe simultaneously.)

Look at the y component of each initial velocity. Ball 2 and 5 both have v₀ᵧ = 0, so they land at the same time. Ball 4 has the highest downwards velocity, so it will land first. Logically, Ball 3 will land after 4 and before 2 and 5. Ball 1 will take the longest to land.

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snehashish65 snehashish65 · Answer 2 · 2021-12-13T06:16:15+01:00

The ball 1 will take longest time to hit the ground while ball 4 will take shortest time as per the ranking,

Ball 4 < Ball 3 < Ball 2 = Ball 5 < Ball 1

Given data:

Four balls are simultaneously launched with the same speed from the same height and h above the ground.

And at the same instant, the ball 5 is released from the rest at the same height.

From the given picture and considering all the logical aspects, we need to consider the y component of initial velocity of each ball.

Ball 2 and 5 both have v₀ᵧ = 0, so they land at the same time. Ball 4 has the highest downwards velocity, so it will land first. Logically, Ball 3 will land after 4 and before 2 and 5. Ball 1 will take the longest time to land.

So, the ranking will be in the order from the least to long as,

Ball 4 < Ball 3 < Ball 2 = Ball 5 < Ball 1

Thus, we can conclude that the ball 1 will take longest time to hit the ground while ball 4 will take shortest time as per the ranking,

Ball 4 < Ball 3 < Ball 2 = Ball 5 < Ball 1

For more details, refer to the link below:

https://brainly.com/question/3953395