Answer:
The molar mass of the gas is 32.03 g/mol
Explanation:
Pressure of gas = P = 0.961 atm
Volume occupied by gas = V = 1.00 L
Temperature = T = 27[tex]^{\circ}C[/tex] = 300 K
Assuming M g/mol be the molar mass of the gas and the gas behaves as an ideal gas.
The ideal gas equation is shown below
[tex]\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\0.961 \textrm{ atm}\times 1.00 \textrm{ L} = \displaystyle \frac{1.25 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 300\textrm{K} \\M = 32.03 \textrm{ g/mol}[/tex]
Molar mass of given sample of gas = 32.03 g/mol
