Answer:
[tex]x=st[/tex]
[tex]y=-5t[/tex]
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
so
The distance is equal to multiply the speed by the time
Let
s ----> the speed in units per second
d ---> the distance in units
t ---> is the time in seconds
BUG A
we have
[tex]d=18\ units[/tex]
[tex]t=3\ sec[/tex]
The speed is equal to
[tex]s=\frac{d}{t}[/tex]
substitute
[tex]s=\frac{18}{3}=6\ units/sec[/tex]
If x is the point reached by A after t seconds
then
Multiply the speed by the time
[tex]x=st[/tex]
[tex]x=6t[/tex]
BUG B
we have
[tex]d=-15\ units[/tex]
[tex]t=3\ sec[/tex]
The speed is equal to
[tex]s=\frac{d}{t}[/tex]
substitute
[tex]s=\frac{15}{3}=5\ units/sec[/tex]
If y is the point reached by B after t seconds
then
Multiply the speed by the time
[tex]y=st[/tex]
[tex]y=-5t[/tex] ----> is negative because B is moving in the negative direction
Answer:
x = 6t
y = 5t
Step-by-step explanation:
We know the distance formula:
D = RT
Where
D is distance
R is speed
T is time
Bug A went 18 units after 3 seconds, so the speed is:
18 = R(3)
R = 18/3
R = 6 unit/sec
Bug B went 15 units in 3 seconds, so the speed is:
15 = R(3)
R = 15/3
R = 5 units/sec
x is reached by A after 3 seconds, so
x = 6t
y is reached by B after 3 seconds, so
y = 5t
