Find the value of R2 required if vs = 18 V , R1 = 50 kΩ , and the desired no-load output voltage is vo = 6 VPart b)Several different loads are going to be used with the voltage divider from Part A. If the load resistances are 300 kΩ , 200 kΩ , and 100 kΩ , what is the output voltage that is the most different from the design output voltage vo = 6 V ?part c)The circuit designer wants to change the values of R1 and R2 so that the design output voltage vo = 6 V is achieved when the load resistance is RL = 200 kΩ rather than at no-load. The actual output voltage must not drop below 5.4 V when RL = 100 kΩ . What is the smallest resistor value that can be used forR1?

Respuesta :

Answer:

R2=25kΩ b) For 100kΩ c) R1=80kΩ and R2=50kΩ; R2=130 kΩand R1>130kΩ

Explanation:

For this question consider the circuit in the attachment

Vs-Vo=IR1

12=I(50000)

I=12/50 mA

Vo=IR2

6=(12/50)×R2

R2=25kΩ

b) For Resistances in parallel

Rt=(Rl×R2)/(Rl+R2)

For RL=300

Rt=23.08

Vo=Rt/(Rt+R1) ×Vs

Vo=5.68V

For RL=200

Rt=22.2

Vo=5.53V

For RL=100

Rt=20

Vo=5.14V

c) For Vo=6V, R1=2Rt

If R2=50kΩ and R1=80kΩ when RL=200kΩ

then Rt=40kΩ

and Vo=6V

Let's suppose R2=130kΩ and R1=130kΩ

Rt=(130×100)/(130+100)

Rt=56.52kΩ

Vo=56.52/(56.52+130) ×18

Vo=5.45V

Now if R1=130kΩ and R2=125kΩ

Vo=5.389V

Now if R1=125kΩ and R2=125kΩ

Vo=5.54V

So R1

So in order for Vo≥5.4V

R2=130 kΩand R1>130kΩ

Ver imagen hafsaabdulhai

Answer:

Explanation:

Check attachment for solution

Ver imagen Kazeemsodikisola
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