You need a 40% alcohol solution. On hand, you have a 100 mL of a 25% alcohol mixture. You also have 65% alcohol mixture. How much of the 65% mixture will you need to add to obtain the desired solution

Respuesta :

Answer: 60 ml of the 65% mixture will you need to add to obtain the desired solution.

Explanation:

According to the dilution law,

[tex]C_1V_1+C_2V_2=C_3V_3[/tex]

where,

= concentration of given alcohol solution = 25 %

[tex]V_1[/tex] = volume of given alcohol solution = 100 ml

[tex]C_2[/tex] = concentration of another alcohol solution=65 %

[tex]V_2[/tex] = volume of another acid solution= x ml

[tex]C_3[/tex]  = concentration of resulting alcohol solution = 40 %

[tex]V_3[/tex] = volume of resulting acid solution = (100+x)

[tex]25\times 100+65\times x=40\times (100+x)[/tex]

[tex]x=60ml[/tex]

Thus 60 ml of the 65% mixture will you need to add to obtain the desired solution.

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