Answer:
The black poodle is true breeding (homozygous) for the black fur colour.
Explanation:
Let the allele for fur colour be represented by B.
Black fur (B) is dominant over white fur (b).
Black poodle (B _) is crossed with white poodle (bb):
B _ x bb
Progeny (all black) = Bb, Bb, _b and _b.
Since all the progeny are black, _b = Bb (remember, B is dominant over b)
Hence, B_ is also BB.
The best conclusion is that the black poodle is true breeding (homozygous) for the black fur colour.
