Respuesta :
Explanation:
Formula to calculate osmotic pressure is as follows.
Osmotic pressure = concentration × gas constant × temperature( in K)
Temperature = [tex]25^{o} C[/tex]
= (25 + 273) K
= 298.15 K
Osmotic pressure = 531 mm Hg or 0.698 atm (as 1 mm Hg = 0.00131)
Putting the given values into the above formula as follows.
0.698 = [tex]C \times 0.082 \times 298.15 K [/tex]
C = 0.0285
This also means that,
[tex]\frac{\text{moles}}{\text{volume (in L)}}[/tex] = 0.0285
So, moles = 0.0285 × volume (in L)
= 0.0285 × 0.100
= [tex]2.85 \times 10^{-3 }[/tex]
Now, let us assume that mass of [tex]C_{12}H_{23}O_{5}N[/tex] = x grams
And, mass of [tex]C_{12}H{22}O_{11}[/tex] = (1.00 - x)
So, moles of [tex]C_{12}H_{23}O_{5}N = \frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{x}{369}[/tex]
Now, moles of [tex]C_{12}H_{22}O_{11} = \frac{(1.00 - x)}{342}[/tex]
= [tex]\frac{x}{369} + \frac{(1.00 - x)}{342}[/tex]
= [tex]2.85 \times 10^{-3}[/tex]
= x = 0.346
Therefore, we can conclude that amount of [tex]C_{12}H_{23}O_{5}N[/tex] present is 0.346 g and amount of [tex]C_{12}H_{22}O_{11}[/tex] present is (1 - 0.346) g = 0.654 g.
