A certain bakery has 6 employees. It pays annual salaries of $14,000 to each of 2 employees, $16,000 to 1 employee, and $17,000 to each of the remaining 3 employees. The average (arithmetic mean) annual salary of these employees is closest to which of the following

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Answer:

Option C) $15,800 is the answer.

Explanation:

First, it is necessary to remember that there are 6 employees in the bakery.

We have to add all the annual salaries:

14,000*2=28,000

16,000*1=16,000

17,000*3=51,000

28,000+16,000+51,000=95,000.

Finally, we most divide the following:

95,000/6=$15,833.3 and the closest amount to this one is option C, $15,800.

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