Answer:
Ca(OH)2(s) + 2HCl(aq) → CaCl2(aq) + 2H2O(l)
Explanation:
Step 1: Data given
Mass of Ca(OH)2 = 9.49 grams
Volume of a 0.490 M HCl solution = 30.0 mL = 0.030 L
Step 2: The unbalanced equation
Ca(OH)2 + HCl → CaCl2 + H2O
On the left side we have 2x O (in Ca(OH)2 ) and on the right side we have 1x O (in H2O). To balance the amount of O we have to multiply H2O, on the right side , by 2.
Ca(OH)2 + HCl → CaCl2 + 2H2O
On the right side we have 4x H (in 2H2O), and on the left side we have 3x H (2x in Ca(OH)2 and 1x in HCl). To multiply the amount of H, we have to multiply HCl on the left side by 2.
Ca(OH)2(s) + 2HCl(aq) → CaCl2(aq) + 2H2O(l)