Respuesta :
Answer: 4.3KN
Explanation:f=m(v-u)/t
m=0.77kg
t=0.0029s
s=16.2m/s
F= 0.77*16.2/0.0029
F=12.474/0.0029
F= 4301.38N
F=4.3KN
The average force is inversely proportional to the time interval. The average force acting on the object is 4.3 N during the 2.9 s time interval.
From Average Force:
[tex]F=\dfrac {m(v-u)}{t}[/tex]
Where,
[tex]m[/tex]- mass = 0.77 kg
[tex]t[/tex] - time =0.0029 s
[tex]v[/tex] - final velocity =16.2 m/s
[tex]u[/tex] - initial velocity = 0 m/s
Put the values in the equation,
[tex]F = \dfrac {0.77\times (16.2 - 0)}{0.0029}\\\\F =4.3 \rm \ N[/tex]
Therefore, the average force acting on the object is 4.3 N during the 2.9 s time interval.
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