Answer:
The horizontal distance travelled by an arrow is 70.6 m.
Step-by-step explanation:
Given : An archery arrow is shot with a speed of 45 m/s at an angle of 10°.
To find : How for horizontally can the arrow travel before hitting a target at the same height from which it was released?
Solution :
The expression for the range of the projectile motion is
[tex]R=\frac{V^2\sin 2\theta}{g}[/tex]
Where, the velocity of an arrow is V = 45 m / s
The angle of release of an arrow is [tex]\theta=10^\circ[/tex]
The acceleration due to gravity is g =9.81 m/s²
Substitute the values,
[tex]R=\frac{45^2\sin 2(10)}{9.81}[/tex]
[tex]R=\frac{2025\sin (20)}{9.81}[/tex]
[tex]R=70.6\ m[/tex]
Therefore, the horizontal distance travelled by an arrow is 70.6 m.
