Answer:
Where the height of the cap is less than or equal to the radius of the bore of the plastic pipe then the ⇵⇵shear stress is less than o equal to 60 psi.
Explanation:
Shear stress = F/A
where F = Applied force
A = Cross sectional area of the member experiencing the force
If the cap covers a section of the pipe of height, h then the area = 2πrh
Where the 60 psi pressure is acting on the pipe bore, we have P₀ = 60 psi = F₀/A₀ where A₀ = area of pipe bore ≈ πr². Therefore if F₀ = F then we have
F₀/A₀ = F₀/πr² and F/A = F₀/2πrh = where h greater than or equal to 0.5×r then the shear stress is less than or equal to 60 psi
