Answer: The slope of BC is -2.
Step-by-step explanation:
We know that a rectangle has all opposite sides equal and parallel.
Each interior angle is a right angle.
Therefore , if rectangle ABCD is a rectangle then , AB should perpendicular to BC. [ ∵ Angle between AB and BC is 90° .] (1)
Also , slope of line passing through (a,b) and (c,d) : [tex]\dfrac{d-b}{c-a}[/tex]
If A is located at (3, 4) and B is located at (7,6) .
Then , The slope of AB = [tex]\dfrac{6-4}{7-3}=\dfrac{2}{4}=\dfrac{1}{2}[/tex]
Also, the product of slopes of two perpendicular lines is -1.
Then , (Slope of AB) x (Slope of BC) = -1 [From (1)]
[tex]\Rightarrow\ \dfrac{1}{2}\times (\text{Slope of BC})= -1\\\\\Rightarrow\ \text{Slope of BC}=-2[/tex]
Hence, the slope of BC is -2.
