3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a particular survey 15,000 households are contacted, what is the probability that at least 1,500 will agree to respond

Respuesta :

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

In this problem, we have that:

[tex]n = 15000, p = 0.09[/tex]

So

[tex]\mu = E(X) = np = 15000*0.09 = 1350[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05[/tex]

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1499 - 1350}{35.05}[/tex]

[tex]Z = 4.25[/tex]

[tex]Z = 4.25[/tex] has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

The probability that at least 1,500 will agree to respond is 0.000009.

How to calculate the probability

From the information given,

n = 15000

p = 0.09

Therefore, np = 15000 × 0.09

= 1350

nq = 15000 × (0.91)

= 13650

The probability that at least 1,500 will agree to respond will be:

= 1 - P (Z < (1500 - 1350)/35.05]

= 1 - P(Z < 4.2796)

= 0.000009

Learn more about probability on:

https://brainly.com/question/25870256

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