Respuesta :
Answer:
a) F = 2.2275 * 10^-4 N , upwards
b) F = 2.2275 * 10^-4 N , east to west
c) F = 0
Explanation:
Given:
- The straight wire of length L = 2.7 m
- The current I in the wire I = 1.50 A
- The magnetic Field B = 0.55 * 10^-4 T
Find:
Find the magnitude and direction of the force that our planet’s magnetic field exerts on this wire if it is oriented so that the current in it is running
a) from west to east
b) vertically upward
c) from north to south
d) Is the magnetic force ever large enough to cause significant effects under normal household conditions?
Solution:
- If current runs from west to east the angle between the magnetic field B is θ = 90°, so the magnitude of force due to magnetic field is given by Lorentz force.
F = B*I*L*sin(θ)
F = 0.55*1.5*2.7*sin(90)*10^-4
F = 2.2275 * 10^-4 N
- From Figure B points north and current I points east. From right hand rule, the direction of force is out of page, so its upward.
- If current runs upward the angle between the magnetic field B is θ = 90°, so the magnitude of force due to magnetic field is given by Lorentz force.
F = B*I*L*sin(θ)
F = 0.55*1.5*2.7*sin(90)*10^-4
F = 2.2275 * 10^-4 N
- From Figure B points north and current I points out of page . From right hand rule, the direction of force is out of page, so its east to west.
- If current runs north to south the angle between the magnetic field B is θ = 0°, so the magnitude of force due to magnetic field is given by Lorentz force.
F = B*I*L*sin(θ)
F = 0.55*1.5*2.7*sin(0)*10^-4
F = 0 N
The magnitude of the force that our planet's magnetic field exerts is mathematically given as
F=1.82* 10^{-4}N
What is the magnitude of the force that our planet's magnetic field exerts on this cord?
Question Parameter(s):
A straight 2.70 m wire carries a typical household current of 1.50
the earth's magnetic field is 0.550 gauss
Generally, the equation for the force exerted by the magnetic field is mathematically given as
F=ILB
Where
B=0.550 G
B= 0.55 *10^{-4}T
In conclusion,force exerted by the magnetic field is
F=(1.50 A)(2.20 m)(0.55* 10^{-4} T)
F=1.82* 10^{-4}N
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Complete Question
A straight 2.70 m wire carries a typical household current of 1.50 an (in one direction) at a location where the earth's magnetic field is 0.550 gauss from south to north.
Find the magnitude of the force that our planet's magnetic field exerts on this cord if is oriented so that the current in it is running from west to east
