Answer:
3 moles of [tex]Cl^{-}[/tex] is needed for [tex]Na^{+}[/tex]to be fully consumed.
Explanation:
For the balanced equation:
[tex]Na^{+} + Cl^{-}[/tex] ⇒ [tex]NaCl[/tex]
First, find the moles of Na corresponding to the 69g used the general definition of mol:
[tex]mol Na^{+} = \frac{69 g}{23 g/mol } = 3mol[/tex]
We observe that the equation is balanced and the stoichiometric ratio between them is 1: 1.
According to this, one mole of Na will react with one mole of Cl.
3 moles of [tex]Cl^{-}[/tex] is needed for [tex]Na^{+}[/tex]to be fully consumed.