Answer:
Option B) 31.348
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 49
Sample standard deviation, s = 2.6 minutes
Population standard deviation, [tex]\sigma[/tex] = 2.9 minutes
Significance level, [tex]\alpha[/tex] = 0.05
We have o find the test statistic.
Formula:
[tex]\chi^2 = \dfrac{(n-1)s^2}{\sigma^2}\\\\\chi^2 =\displaystyle\frac{(40-1)(2.6)^2}{(2.9)^2}\\\\\chi^2=31.348[/tex]
Thus, the test statistic is
Option B) 31.348
