Answer:
Correct answer: First answer is true
Step-by-step explanation:
Where x is independently variable and refers to the elapsed time and
( i-d )(x) is a function or dependent variable and shows the number of gallons during that time.
f (x) = ( i-d )₍ₓ₎ = 3 x² + 2 - ( 4 x - 1) = 3 x² - 4 x + 3
( i-d )₍ₓ₎ = 3 x² - 4 x + 3
( i-d ) (3) = 3 · 3² - 4 · 3 + 3 = 27 - 12 + 3 = 18
( i-d ) (3) = 18 gallons after 3 hours in the tank
God is with you!!!
There are 18 gallons of liquid in the tank at t = 3 hours
The liquid tank has both an inlet pipe to add liquid and a drain pipe to drain liquid from the tank.
The modeled function of inlet pipe = i(x) = 3[tex]x^{2}[/tex]+2
The modeled function of drain pipe = d(x) = 4x-1 ,
where the rate is measured in gallons per hour in both functions.
(i-d)(x) = 3[tex]x^{2}[/tex]+2-(4x-1)
⇒ (i-d)(x) = 3[tex]x^{2}[/tex]+2-4x+1
⇒ (i-d)(x) = 3[tex]x^{2}[/tex]-4x+3
⇒ (i-d)(3) = 3×[tex]3^{2}[/tex]-4×3+3
⇒ (i-d)(3) = 27-12+3
⇒ (i-d)(3) = 18
Learn more about tank problem here :
https://brainly.com/question/14975917
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