Prove the superposition principle for nonhomogeneous equations. Suppose that y1 is a solution to Ly1 = f(x) and y2 is a solution to Ly2 = g(x) (same linear operator L). Show that y = y1 + y2 solves Ly = f(x) + g(x). Differential Equation.

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Answer:

Step-by-step explanation:

Given Data

Suppose That [tex]y_{1}[/tex] is a solution of L[tex]y_{1}[/tex] = F(x)

and [tex]y_{2}[/tex] is a solution  of [tex]Ly_{2}[/tex] = g(x)

L is liner operator

∴ [tex]L(y_{1}+y_{2} )[/tex] = L[tex]y_{1}[/tex] +[tex]Ly_{2}[/tex]

L(y) = F(x) + g(x)

[tex]y_{1}+y_{2}[/tex] is the solution to  L(y) = F(x) + g(x)

E.g the liner operator be L = [tex]\frac{d}{dx}[/tex]

[tex]\frac{d}{dx}[/tex] [tex]y_{1}[/tex]  = f(x)

[tex]\frac{d}{dx}[/tex] [tex]y_{2}[/tex] = g(x)

[tex]\frac{d}{dx}[/tex] [tex](y_{1}+y_{2} )[/tex] = [tex]\frac{d}{dx}[/tex] [tex]y_{1}[/tex] + [tex]\frac{d}{dx}[/tex] [tex]y_{2}[/tex] = f(x) + g(x)

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