Respuesta :
The given question is incomplete. The complete question is:
A 10.0 mL aliquot is removed from the described stock solution with molarity of 5M and diluted to a total volume of 100.0 mL. Calculate the molarity of the dilute solution.
Answer: 0.5 M
Explanation:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock solution = 5 M
[tex]V_1[/tex] = volume of stock solution = 10.0 ml ml
[tex]M_2[/tex] = molarity of dilute solution = ?
[tex]V_2[/tex]= volume of dilute solution = 100.0 ml
Putting in the values we get:
[tex]5M\times 10.0=M_2\times 100.0[/tex]
[tex]M_2=0.5M[/tex]
Thus the molarity of the dilute solution is 0.5 M
The molarity of the dilute solution is 0.5 M.
The given parameters;
- initial volume of the liquid, V₁ = 10 mL
- volume of the diluted solution, V₂ = 100 mL
- Concentration of the initial stock, C = 5 M
The molarity of the dilute solution is calculated as follows;
[tex]C_{stock} = D.F \times c_{dilute}[/tex]
where;
D.F is dilute factor
The dilute factor of the given solution is calculated as follows;
[tex]D.F = \frac{V_{dilute}}{V_{concentrate}} \\\\D.F = \frac{100}{10} \\\\D.F = 10[/tex]
[tex]C_{stock} = D.F \times c_{dilute}[/tex]
[tex]5 = D.F \times c_{dilute}\\\\c_{dilute} = \frac{5}{DF} \\\\c_{dilute} = \frac{5}{10} \\\\c_{dilute} = 0.5 \ M[/tex]
Thus, the molarity of the dilute solution is 0.5 M.
"Your question is incomplete, it seems to be missing the following information":
A 10.0 mL of a liquid is removed from the described stock solution with molarity of 5M and diluted to a total volume of 100.0 mL. Calculate the molarity of the dilute solution.
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