Answer:
Li₂SO₄ is the formed salt
Explanation:
We determine the reactants dissociations:
H₂SO₄ → 2H⁺ + SO₄⁻²
LiOH → Li⁺ + OH⁻
The 2H⁺ link the OH⁻ to form water, but there is one more H⁺, so we need another OH⁻ to finally produce 2 moles of H₂O
In conclussion to determine the lithium sulfate, which is the formed salt, Li will release 2 e⁻ as this equation shows:
2Li → 2Li⁺ + 2e⁻
Now the neutralization reaction is:
2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O
