Answer:
[tex]9.7\times 10^{-5} T[/tex]
Explanation:
Velocity =[tex]5\times 10^4i-2\times 10^4j[/tex]
r=[tex]0.03i+0.05j[/tex]
r=[tex]\mid r\mid=\sqrt{(0.03)^2+(0.05)^2}=0.058[/tex]
v=[tex]\mid V\mid=\sqrt{(5\times 10^4)^2+(-2\times 10^{4})^2}=5.39\times 10^{2}[/tex]
We know that
[tex]B=\frac{mv}{qr}[/tex]
Where q=[tex]1.6\times 10^{-19} C[/tex]
Mass of proton=[tex]1.67\times 10^{-27} kg[/tex]
Using the formula
[tex]B=\frac{1.67\times 10^{-27}\times 5.39\times 10^2}{1.6\times 10^{-19}\times 0.058}[/tex]
[tex]B=9.7\times 10^{-5} T[/tex]
