How do you do this question?
Answer:
x={1,2,3}
Step-by-step explanation:
The given inequality is
[tex]1 \leqslant \frac{6x - 1}{3} \: < \: 7[/tex]
We multiply through by the LCM of 3 to get:
[tex]3\leqslant 6x - 1\: < \: 21[/tex]
We add 1 to both sides to get:
[tex]3 + 1\leqslant 6x \: < \: 21 + 1[/tex]
[tex]4\leqslant 6x \: < \: 22[/tex]
Divide through by 6 to get:
[tex] \frac{4}{6} \leqslant x \: < \: \frac{22}{6} [/tex]
This gives us:
[tex]\frac{2}{3} \leqslant x \: < \: \frac{11}{3} [/tex]
[tex]0.67 \leqslant x \: < \:3.67[/tex]
Since x is an integer, the possible values are:
x={1,2,3}