Answer:
[tex]6\times 10^{10}\ Hz[/tex]
Explanation:
d = Slit gap = 5 mm
Slit distance = 16 cm
c = Speed of light = [tex]3\times 10^8\ m/s[/tex]
[tex]\lambda[/tex] = Wavelength
We have the relation
[tex]dsin\theta=\lambda[/tex]
Here, [tex]\theta=90[/tex]
So
[tex]d=\lambda\\\Rightarrow \lambda=5\ mm[/tex]
Frequency is given by
[tex]f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{5\times 10^{-3}}\\\Rightarrow f=6\times 10^{10}\ Hz[/tex]
The frequency is [tex]6\times 10^{10}\ Hz[/tex]
