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A woman with Turner syndrome is found to be color-blind (an X-linked recessive phenotype). Both her mother and her father have normal vision. a. Explain the simultaneous origin of Turner syndrome and color blindness by the abnormal behavior of chromosomes at meiosis. b. Can your explanation distinguish whether the abnormal chromosome behavior occurred in the father or the mother? c. Can your explanation distinguish whether the abnormal chromosome behavior occurred at the first or second division of meiosis? d. Now assume that a color-blind Klinefelter man has parents with normal vision, and answer parts a, b, and c

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Histrionicus

Answer:

A) The turner syndrome is characterized by lacking half chromosome numbers which are also termed as the monosomy as there is only half the number of X linked chromosomes that are responsible for the colorblindness will be greater. The chances are 50% of having this disorder in such a case.

B) The correct answer would be no, as the error will be shown in only one of the due to n number of chromosomes present in both parents.

C) Anaphase II of meiosis II it takes places as here only the strands are pulled to opposite poles of the cell

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D) Assuming it as Klinefelter man with colorblindness has normal parents then,

a)double XX +Y , the colorblind gene is recessive in XX and Y. or recessive in XX but dominating Y only rules out the other recessive.

b) Explanation is similar as B)

c) Due to a nondisjunction event during meiosis, I or meiosis II in the female X chromosome is still present in it.

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