Respuesta :
Answer:
The average force is 1578.94 N.
Explanation:
Given that,
Mass of baseball = 150 g
Speed = 45 m/s
Speed of pitcher = 60 m/s
Time = 9.5 ms
We need to calculate the average force
Using formula of impulse
[tex]J=\Delta p[/tex]
[tex]J=m\Delta v[/tex]...(I)
[tex]J=F\Delta t[/tex]....(II)
From equation (I) and (II)
[tex]F=\dfrac{m(v_{f}-v_{i})}{\Delta t}[/tex]
Where, m = mass of baseball
[tex]v_{f}[/tex] = final velocity
[tex]v_{i}[/tex] = Initial velocity
[tex]\Delta t[/tex] = time
Put the value into the formula
[tex]F=\dfrac{150\times10^{-3}\times(60-(-40))}{9.5\times10^{-3}}[/tex]
[tex]F=1578.94\ N[/tex]
Hence, The average force is 1578.94 N.
Answer:
F = 1657.89 N
Explanation:
given,
mass of the baseball, m = 150 g
initial speed, u = 45 m/s
final speed, v = 60 m/s
time of contact,t = 9.5 ms
we know,
impulse is equal to change in momentum
J = m (v - u)
J = 0.15 x (60-(-45))
J = 0.15 x 105
J = 15.75 Kg.m/s
We also know that impulse
J = F x Δ t
F x 9.5 x 10⁻³ = 15.75
F = 1657.89 N
The magnitude of the average force is equal to F = 1657.89 N
