Decrease in temperature is -126.0°C
Explanation:
Using Charles law we can set up the equation as,
V₁/T₁ = V₂/T₂
(2.00 L) / 294.0 K) = (1.00 L) / (x)
cross multiply to get:
2x = 294
2x/2 = 294/2
x = 147.0 K
Now kelvin is converted into Celsius by subtracting 273 from 147 as,
147 - 273 = -126°C
Given that:
Volume,
Temperature,
By using Charles Law, we get
→ [tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]
By substituting the values, we get
[tex]\frac{2.00}{294.0} = \frac{1.00 \ L}{x}[/tex]
[tex]2x = 294[/tex]
[tex]x = \frac{294}{2}[/tex]
[tex]= 147.0 \ K[/tex]
By converting "Kelvin" into "Celsius", we get
= [tex]147-273[/tex]
= [tex]- 126^{\circ} C[/tex]
Thus the response above is correct.
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