Answer:
Bit rate = 440 kBits/sec
Step-by-step explanation:
Band width = W= 22 kHz
Number of levels = L = 1024 levels
Bit per sample:
[tex]m=log_2 L\\\\m =log_2(1024)\\\\m=10 bits/sample[/tex]
Ideal pulses are sent at the Nyquist rate then bit rate = 2 x W x m
[tex]bit\,\,rate= 2\times 22\times 10^3\times 10\\\\bit\,\,rate= 440\times 10^3 bits\,sec^{-1}[/tex]
bit rate = 440 kBits/sec
