Respuesta :
Answer:
The tangential speed of a point on the "equator" of the baseball is 4.33 m/s.
Explanation:
Given that,
Linear speed of base ball = 42.5 m/s
Distance = 16.0 m
Angle = 44.5 rad
Radius of baseball = 3.67 cm
We need to calculate the flight time
Using formula of time
[tex]t=\dfrac{d}{v}[/tex]
Put the value into the formula
[tex]t=\dfrac{16.0}{42.5}[/tex]
[tex]t=0.376\ sec[/tex]
We need to calculate the number of rotation
Using formula of number of rotation
[tex]n=\theta\time 2\pi[/tex]
[tex]n=\dfrac{44.5}{2\pi}[/tex]
[tex]n=7.08[/tex]
We need to calculate the time for one rotation
Using formula of time
[tex]T=\dfrac{t}{n}[/tex]
Put the value into the formula
[tex]T=\dfrac{0.376}{7.08}[/tex]
[tex]T=0.053\ sec[/tex]
We need to calculate the circumference
Using formula of circumference
[tex]C=2\pi\times r[/tex]
Put the value into the formula
[tex]C=2\pi\times3.67\times10^{-2}[/tex]
[tex]C=0.23\ m[/tex]
The tangential speed is equal to the circumference divided by the time. it takes to complete one rotation.
We need to calculate the tangential speed
Using formula of tangential speed
[tex]v=\dfrac{C}{T}[/tex]
Put the value into the formula
[tex]v=\dfrac{0.23}{0.053}[/tex]
[tex]v=4.33\ m/s[/tex]
Hence, The tangential speed of a point on the "equator" of the baseball is 4.33 m/s.
