Answer:
a.264.6m/s
b.4995g
Explanation:
Data given,
Tension T=500N,
length of wire=0.7m,
mass,m=5g=0.005kg
a.To determine the speed of the transverse wave, we use the equation below
[tex]V=\sqrt{\frac{FL}{m} } \\F=tension, L=length, m=mass\\[/tex]
if we insert values as given in the question , we arrive at
[tex]V=\sqrt{\frac{500*0.7}{0.005}}\\ V=264.6m/s[/tex]
b. To reduce he wave speed by a factor of 2, the new wave speed will become 132.3m/s.
From the equation, if mass,m becomes subject of formula, we have
[tex]m=\frac{V^{2}}{FL}\\ m=\frac{132.3^{2}}{500*0.7}\\m=50kg\\m=5000g[/tex]
Hence to reduce the speed by a factor of 2, (5000-5)g=4995g mass of copper wire would have to be wrapped around the wire.
