Rank the following compounds in order of decreasing boiling point: potassium fluoride (KF), carbon tetrafluoride (CF4), and iodomethane (CH3I) Rank from highest to lowest boiling point. To rank items as equivalent, overlap them.

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05-02-2020
Chemistry

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Rank the following compounds in order of decreasing boiling point: potassium fluoride (KF), carbon tetrafluoride (CF4), and iodomethane (CH3I) Rank from highest to lowest boiling point. To rank items as equivalent, overlap them.

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OlaMacgregor OlaMacgregor · Answer 1 · 2020-02-06T06:28:54+01:00

Explanation:

Ionic compounds have high boiling point due to the presence of strong intermolecular forces present within the molecules due to the partial opposite charges on its atoms.

For example, KF is an ionic compound so it has high boiling point.

Whereas covalent compounds have weak forces because of sharing of electrons taking place between the molecules of a substance.

Whereas [tex]CF_{4}[/tex] is a covalent compound as both the atoms are non-metals. Hence, it has low boiling point.

In [tex]CH_{3}I[/tex], there is dipole moment. Hence, it will have a boiling point greater than [tex]CF_{4}[/tex].

Therefore, we can conclude that order of decreasing boiling point of given compounds is as follows.

[tex]KF > CH_{3} > CF_{4}[/tex]