Answer:
48.38 g of Na3PO4
Explanation:
Na3PO4(s) + H2O(l) ---> 3Na+ + PO4^3-
By stoichiometry, 1 mole of Na3PO4 will dissociate in water to give 3 moles of Na+
Moles of Na+ = concentration of Na+/volume
= 0.545/615 x 10^-3
= 0.886 moles
1 mole of Na+ will be got from 0.33moles of Na3PO4
0.886 moles will be dissociated from 0.333 * 0.886 moles of Na3PO4
Moles of Na3PO4 = 0.295mol
Mass of Na3PO4 = molar mass * mass
Molecular weight = (23*3) + (31*1) + (16*4)
= 164 g/mol
Mass of Na3PO4 = 164 * 0.295
= 48.38 g of Na3PO4
