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The osmotic pressure, Π, of a solution of glucose is 83.1 atm . Find the molarity of the solution at 298 K. Express the molarity to three significant figures and include the appropriate units.

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Answer:

Molarity for this solution is: 3.40 mol/L

Explanation:

Osmotic pressure is the colligative property which formula is:

π = M . R . T

83.1 atm = M . 0.082 L.atm/mol.K . 298K

83.1 atm / (0.082 L.atm/mol.K . 298K) = M

As you see all the units are cancelled, except for mol/L which means certainly Molarity

83.1 atm / (0.082 L.atm/mol.K . 298K) = 3.40 mol/L

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