Answer:
Step-by-step explanation:
Given system of equations are
y= -3x+4
⇔3x+y=4 .........(1)
x= 2y+6
⇔x-2y=6...........(2)
Equation (1) ×2 +equation (2)
6x +2y+x-2y =8+6
⇔7x=14
[tex]\Leftrightarrow x= \frac{14}{7}[/tex]
⇔x = 2
Putting the value of x in equation (1)
3.2+y=4
⇔y+6=4
⇔y=4-6
⇔y=-2
Therefore x=2 and y=-2
