Answer:
Explanation:
Given
Load [tex]W=20000\ N[/tex]
height to which load is raised [tex]h=250\ m[/tex]
Another crane take [tex]\frac{1}{6}[/tex] th time to lift the load
Energy required required to lift the Weight
[tex]E=W\times h[/tex]
[tex]E=20000\times 250[/tex]
[tex]E=5,000,000\ J[/tex]
Suppose [tex]P_1[/tex] and [tex]P_2[/tex] is the Power required to lift the weight in t and [tex]\frac{t}{6}[/tex] time
[tex]E=P_1\times t[/tex]
[tex]E=P_2\times \frac{t}{6}[/tex]
[tex]P_1\times t=P_2\times \frac{t}{6}[/tex]
thus
[tex]P_2=6P_1[/tex]
Second Crane requires 6 times more power than the slow crane
