Explanation:
The given data is as follows.
Dry mass of soil ([tex]m_{d}[/tex]) = [tex]m_{2} - m_{1}[/tex] = 500 g
[tex]m_{3}[/tex] = jar + soil + water = 1697 g
[tex]m_{4}[/tex] = weight of jam + water = 1390 g
[tex]m_{2}[/tex] = bottle + dry soil
[tex]m_{1}[/tex] = weight of empty bottle
Formula to calculate specific gravity is as follows.
Specific gravity = [tex]\frac{\text{dry mass of fossil}}{\text{mass of water of equal volume}}[/tex]
= [tex]\frac{m_{2} - m_{1}}{(m_{4} - m_{1}) - (m_{3} - m_{2})}[/tex]
= [tex]\frac{m_{2} - m_{1}}{(m_{2} - m_{1}) - (m_{3} - m_{4})}[/tex]
= [tex]\frac{500}{(500 - (1697 - 1390)}[/tex]
= 2.59
Thus, we can conclude that value of bulk specific gravity (SSD) of the sand is 2.59.
