Answer:
Coefficient of friction is
Ū = 0.31
Explanation:
T2 = T1* e^(Å«Æ¡)
Where T2 = 7500n = tension in the belt, T1 = 150n = reaction force,
Å« = coefficient of friction
Æ = 2pai * N
Where N = number of turns = 2
Æ = 4pai
7500 = 150e^(Å«*4pai)
50 = e^(Å« *4pai)
lin 50 = 4pai * Å«
Ū = 3.91/4pai
Ū = 0.31
