Au₂S₃
Explanation:
Given compounds:
Gold(I) oxide = Au₂O
Gold(I)sulfide = Au₂S
Gold(III) oxide = Au₂O₃
Gold(III)sulfide = Au₂S₃
Problem: compound with the least mass of Gold.
To solve this problem, we simply find the mass percentage of gold in the given compounds.
Molar mass of Au₂O = 2(197) + 16 = 410g/mole
Molar mass of Au₂S = 2(197) + 32 = 426g/mole
Molar mass of Au₂O₃ = 2(197) + 3(16) = 442g/mole
Molar mass of Au₂S₃ = 2(197) + 3(32) = 490g/mole
The molar mass of gold in all the compound is 394g/mole
Mass percentage of gold in Au₂O = [tex]\frac{394}{410}[/tex] x 100 = 96.1%
Mass percentage of gold in Au₂S = [tex]\frac{394}{426}[/tex] x 100 = 92.5%
Mass percentage of gold in Au₂O₃ = [tex]\frac{394}{442}[/tex] x 100 = 89.1%
Mass percentage of gold in Au₂S₃ = [tex]\frac{394}{490}[/tex] x 100 = 80.4%
Au₂S₃ is the least mass of gold in it
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Answer:
Explanation:
Given compounds:
Gold(I) oxide = Au₂O
Gold(I)sulfide = Au₂S
Gold(III) oxide = Au₂O₃
Gold(III)sulfide = Au₂S₃
Problem: compound with the least mass of Gold.
To solve this problem, we simply find the mass percentage of gold in the given compounds.
Molar mass of Au₂O = 2(197) + 16 = 410g/mole
Molar mass of Au₂S = 2(197) + 32 = 426g/mole
Molar mass of Au₂O₃ = 2(197) + 3(16) = 442g/mole
Molar mass of Au₂S₃ = 2(197) + 3(32) = 490g/mole
The molar mass of gold in all the compound is 394g/mole
Mass percentage of gold in Au₂O = x 100 = 96.1%
Mass percentage of gold in Au₂S = x 100 = 92.5%
Mass percentage of gold in Au₂O₃ = x 100 = 89.1%
Mass percentage of gold in Au₂S₃ = x 100 = 80.4%
Au₂S₃ is the least mass of gold in it
