Respuesta :
Answer : The pH of the solution is, 0.932
Explanation :
First we have to calculate the moles of HCl and NaOH.
[tex]\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.200mole/L\times 0.200L=0.040mole[/tex]
[tex]\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.050mole/L\times 0.100L=0.0050mole[/tex]
The balanced chemical reaction will be,
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
From the balanced reaction we conclude that,
As, 1 mole of NaOH neutralizes by 1 mole of HCl
So, 0.0050 mole of NaOH neutralizes by 0.0050 mole of HCl
Thus, the number of neutralized moles = 0.0050 mole
Remaining moles of HCl = 0.040 - 0.0050 = 0.035 moles
Total volume of solution = 200.0 mL + 100.0 mL = 300.0 mL = 0.300 L
Now we have to calculate the concentration of HCl(acid).
[tex]Concentration=\frac{Moles}{Volume}=\frac{0.035mol}{0.300L}=0.117M[/tex]
As we know that, 1 mole of HCl dissociates to give 1 mole of hydrogen ion and 1 mole of chloride ion.
So, concentration of [tex]H^+[/tex] = 0.117 M
Now we have to calculate the pH of solution.
[tex]pH=-\log [H^+][/tex]
[tex]pH=-\log (0.117)[/tex]
[tex]pH=0.932[/tex]
Thus, the pH of the solution is, 0.932
